Question

What is the inverse of the given relation?
Y=7x^2-3

Answer 1

y=11

Answer 2

Actually no sorry are you in algebra one or two?

Answer 3

wait is 7 mulitplying

Answer 4

I have no clue they Gave me a whole bunch of radicals and exclamations in the answers or I would put them up

Answer 5

3=14x

Answer 6

solve y add 3 divide by 14

Answer 7

A. Y=+ or - sqrt of x+3/7 stuff like this

Answer 8

y+3=7x^2
x^2 = (y+3)/7
x= sqrt((y+3)/7)
so we say :
y=sqrt((x+3)/7)

Answer 9

this is the inverse.. (we solved for x)

Answer 10

y=+/-sqrt((x+3)/7)

Answer 11

just interchange y and x then solve for y!! y=sqrt((x+3)/7)

Answer 12

\[y=7x ^{2}-3\]
\[y-3=7x ^{2}\]
\[\sqrt{\frac{ y-3 }{ 7 }}=x ^{2}\]
So answer will be
\[\pm \sqrt{\frac{ x-3 }{ 7 }}=y\]