Question

dN/dt=A-kN^2 A and k are constants.

Answer 1

What's the question?

Answer 2

solve for n in terms of A and k

Answer 3

the problem is a separation of variables problem

Answer 4

\[\frac{dN}{A-kN^2}=dt \text{ integrate both sides }\]

Answer 5

thanks

Answer 6

let me know if you have problems integrating that
you might have to do cases

Answer 7

you know cases for the constants
when k is negative
when k is positive
when k is zero

Answer 8

k is a constant at 5x10^-6 but i'm supposed to solve it without plugging in the numbers so i guess I assume k is negative then?

Answer 9

5x10^(-6) is positive

Answer 10

You got me...Well i'll just play around with this for a while and see if I can get it, thanks for getting me started!

Answer 11

if I were you and if I knew k and A are positive constants than I would do partial fractions.

Answer 12

Otherwise I might have to consider trig sub.

Answer 13

Then don't say lies about me please