Question

Solve for x

Answer 1

\[3^{2x} -12 \times 3^x +27 =0 \]

Answer 2

I got \[3^{2x}-12 \times 3^x + 3^3 =0\]

But I don't know what I can do with the -12

Answer 3

substitute u = 3^x

\[u^2 - 12u +27 = 0\]

Answer 4

\[(u-9)(u-3)=0\]

Answer 5

\[u=3,9\]\[3^1=3^x or 3^2 = 3^x\]

x = 1, 2

Answer 6

you got it.... correct

Answer 7

Thank you!