Question

Help me Solve another Logarithmic Equation Please

Answer 1

\(\large\color{black}{ \log_{_{\LARGE1/5}}~(x^2+x)-\log_{_{\LARGE1/5}}~(x^2-x) =-1 }\)

Answer 2

this is what I would do (first thing that comes up)

use the rule,
\(\large\color{black}{ \log_{_{\LARGE a}}~(A)-\log_{_{\LARGE a}}~(B) =\log_{_{\LARGE a}}~(\frac{A}{B}) }\)

Answer 3

then when you write it as a single logarithm, re-write the -1 in terms of a log base 1/5.

Answer 4

\[\log_{1/5} = x^2+x/x^2-x (-1) ?\]

Answer 5

at first, when we write this as a single logarithm, using the aforementioned rule,