Question

how do you find points on a parabola (that aren't the zeros) without a graphing calculator?

Answer 1

@iambatman @Miracrown @Kainui @SolomonZelman @triciaal

Answer 2

use the value of x in the function and the result is y value

Answer 3

........? im function is f(x)=-x^5-3x^4+21x^3+47x^2-120x-144

Answer 4

y = f(x)
for a parabola f(x) = ax^2 + bx + c

Answer 5

do i just plug in random numbers for x?

Answer 6

example f(2) means x = 2
y = f(x)=-x^5-3x^4+21x^3+47x^2-120x-144
f(2)= -(2)^5-3*(2)^4 +21*(2)^3 + 47*(2)^2-120*(2)- 144=

Answer 7

oh okay! so i continue doing that until i find a whole number

Answer 8

when you plug in a value for x and the answer is 0 there is no remainder and that value is a factor of the polynomial

Answer 9

this is the same function you had earlier and the zeros were -4, -1 and 3 so when you use these values for x the answer is 0

Answer 10

ok. Thank you!