PLEASE HELP. URGENT. A small software company has two customer service representatives. After a week of observation, the supervisor of the customer service department determines that there is a 61% probability that a customer service representative will be on the phone with a customer at any given time. What is the probability of both representatives being on the phone at the same time? Round to the nearest percent if necessary.

Question

adamaero · Answer

both representatives?
so the probability for each of them is 61%?

anonymous · Answer

There is a 61 percent probability that ONE of the representatives will be on the phone at all times. It's asking what the probability is that BOTH of the representatives will be on the phone at the same time. And it did before c: and I'd change it if I could but I can't haha xD

adamaero · Answer

I would guess (.61+.61)/2 
which equals the mean, but I haven't seen this kind of wording so don't take that answer

anonymous · Answer

hahaha, okay.

adamaero · Answer

@satellite73 need some help @Jhannybean

adamaero · Answer

maybe ask @welligya... 
for advice on how to attract ppl
Even last night a crowd was following her constant, practically the same, questioning

anonymous · Answer

Hahaha, I'm gay, I know how to put a woman's assets to use. Which is weird. But, haha. Yeah, I feel I'll get tons more help when people think I'm a hot girl xD

anonymous · Answer

Two representative being on phone same time are two independent events but not exhaustive,the probability of being both in line is (61/100)*(61/100) ,i.e .6*.6 so approximately 36% chance of both being on phone same time