Question

2x^2+x-1=0 how many real solutions

Answer 1

Let's solve your equation step-by-step.
2x2+x−1=0
Step 1: Factor left side of equation.
(2x−1)(x+1)=0
Step 2: Set factors equal to 0.
2x−1=0 or x+1=0

Answer 2

Answer:x=1/2 or x=−1

Answer 3

if anyone sees the <?> just reload your page...

Answer 4

ok

Answer 5

Thank you so much!

Answer 6

discriminant D=b^2-4ac
\[D=1^2-4*2*-1=1+8=9=3^2>0\]
roots are real and rational.
\[\ because\] it is a qudratic ,so two real roots.