Please help. Im stuck on this bad. Refer to the campground problem from Task 1 on p. 340 of Geometry. Recall that the campsites have the following coordinates: Brighton Bluff at B (2, 2), Ponaganset Peak at P (4, 10), and Harmony Hill at H (12, 2). What are the coordinates of the point where the showers should be placed in order to be equidistant from all three campsites?
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let me see
I never grasped the orthocener, circumcenter, and that fun stuff.
I am really sorry but I can't help
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i think this is the logic to follow
here ya go this is how i found it
Theres an equation that goes along with it. It has something to do with finding the slop of two points and I never understood it.
ok what is this assignment called i will try to google an equation for it
Inequalities of a triangle.. maybe. Try looking for sonething that has to do with concurrency of a triangle with points. Thats what im looking for
is this the equation??
Nope. At least im not the only one with trouble in this problem haha.
have you tried my solution?
Yea, but did you use an equation other than just plotting the points and finding the middle? That is what its asking me.
this is what i got, just needs to be simplified
@briensmarandache did it make sense what i did??
i wasnt sure what you were showing, i just expressed what i told her to do.
To check your answer, the shower should be at (7,5), the blue point in the attached graph
You really have to find the center of the circle passing by the three given points.
no, if you look at the attachment you will see mid point BHPH, that is the center
i have to leave for work if your still stuck ill be on around ten
Yes, if the points are {{2, 2}, {4, 10}, {12, 2}} then my answer is correct. See the picture
@briensmarandache , did you look at the attached circle?
well my answer is different so im not sure by my logic i feel as if im correct but i could be wrong
Let us find the center of the circle that goes to the points {{2,2},{4,10},{12,2}}. Let \[ (x-a)^2 + (y-b)^2 =c\] where c is the square of the radius We need 3 equations let us write them down \[ (2-a)^2+(2-b)^2 =c\\ (4-a)^2+(10-b)^2=c\\ (12-a)^2+(2-b)^2=c \] Wolframalpha will solve them for us to get http://www.wolframalpha.com/input/?i=solve%28+%282-a%29%5E2%2B%282-b%29%5E2+%3Dc%2C+%284-a%29%5E2%2B%2810-b%29%5E2%3Dc%2C+%2812-a%29%5E2%2B%282-b%29%5E2%3D+c+%29 a=7,b=5, c=34
Actually, you can see geometrically why a =7
Thanks for the answer! Your aweomse :) *throws medal*
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