Question

@mathmath333 @jim_thompson5910 @nincompoop

Answer 1

Sorry @Here_to_Help15 Not at that stage of math yet :(

Answer 2

Oh its ok thanks

Answer 3

@mathmath333 @jim_thompson5910

Answer 4

sorry if i am overwhelming you :(

Answer 5

i got AC=32

Answer 6

how do u got that

Answer 7

did you get that* and hold on

Answer 8

DF is to DE as AC is EC or DF/DE=AC/EC or numerically, 16/19=x/38
Where DF=16, DE=19 which is 1/2 of EC (midpoint), X is labeled for AC, and EC is given as 38.

solve for x=AC=608/19=32.
This i what i put down but i need to make it brief and organized thats what i need help on

Answer 9

lol we did this type of problem earlier

Answer 10

yes its \(\Huge \tt \begin{align} \color{black}{\checkmark
}\end{align}\)

Answer 11

Yes i know i am correct lol i need your help on making it brief and organized

Answer 12

How would i do this

Answer 13

@mathmath333 ?

Answer 14

u need to show that
\(\large\tt \begin{align} \color{black}{\triangle EDF \approx \triangle ECA
}\end{align}\)

as \(ED \approx EC\)
\(EF \approx EA\)

by SS theorm

Answer 15

or simpliy bu this

DF/DE=AC/EC

Answer 16

bu?

Answer 17

by

Answer 18

http://www.mathsisfun.com/geometry/triangles-similar-theorems.html

Answer 19

http://www.mathsisfun.com/geometry/triangles-similar-finding.html

Answer 20

At @mathmath333 i need a explanation from you if you don't it seems simpler if that's alright with you?

Answer 21

mind*

Answer 22

do u agree
DF/DE=AC/EC

Answer 23

Yes i agree with that

Answer 24

so by that we can say that trinagle EDF is similar to triangle ECA

Answer 25

do u still agree

Answer 26

yes since they are similar correct?

Answer 27

In other words i agree @mathmath333 i see what you are saying

Answer 28

wait u need to show first that
\(\dfrac{ED}{EC}=\dfrac{EF }{EA}\)

CAN U SHOW THAT

Answer 29

Whats with the caps lol and what do you mean by can i show that

Answer 30

Yes i can type that out if that's what you are saying

Answer 31

can u prove that

Answer 32

Hm let me see

Answer 33

Oh c is g i believe

Answer 34

If we look at the question it doesn't show C

Answer 35

show C?

Answer 36

No lol C is suppose to be G correct? since C is not in the problem

Answer 37

where is G?

Answer 38

OM lol G is SUppose to be C

Answer 39

I mean C IS SUPPOSE TO BE G

Answer 40

\(\large\tt \begin{align} \color{black}{\dfrac{ED}{EC}\\
=\dfrac{ED}{ED+DC}\\
=\dfrac{ED}{ED+ED}\\
=\dfrac{ED}{ED+ED}\\
=\dfrac{1}{2}\\
}\end{align}\)

Answer 41

similarly u have to show that
\(\large\tt \begin{align} \color{black}{\dfrac{EF}{EA}\\

=\dfrac{1}{2}\\
}\end{align}\)

Answer 42

Look at the problem there is no C

Answer 43

C is G correct?

Answer 44

it is C not G

Answer 45

Where does it show C? in the problem

Answer 46

it is called C

Answer 47

Ok nvm :P continue

Answer 48

I just need to sum what i said up

Answer 49

yea nm it happens

Answer 50

But briefly and organize

Answer 51

I want to eat then hit the bed lol

Answer 52

so we proved that \(\dfrac{ED}{EC}=\dfrac{EF }{EA}\)

Answer 53

Yes

Answer 54

hence

\(\large\tt \begin{align} \color{black}{\triangle EDF \approx \triangle ECA
}\end{align}\)

Answer 55

yes

Answer 56

so
\(\dfrac{ED}{EC}=\dfrac{DF }{CA}\)

Answer 57

Ok continue

Answer 58

lol

Answer 59

Oh this irrelevant but i will beat ya at chess

Answer 60

Anyways continue lol

Answer 61

really

Answer 62

yes really lol

Answer 63

ok thats it u need to show

Answer 64

Ok but how @mathmath333 put it this way how would you answer this briefly and organized fit it all in 1 post please

Answer 65

i did it in organized way

Answer 66

Lol fit it in 1 post please

Answer 67

put everything together

Answer 68

after u i showed my last post

continue from here

DF is to DE as AC is EC or DF/DE=AC/EC or numerically, 16/19=x/38
Where DF=16, DE=19 which is 1/2 of EC (midpoint), X is labeled for AC, and EC is given as 38.

solve for x=AC=608/19=32.
This i what i put down but i need to make it brief and organized thats what i need help on

Answer 69

ugh :/

Answer 70

Im just going to turn it in my head hurts :/