Question

Help please? Solve by completing the square. x^2-10x+25=144

Answer 1

\(x^2+bx+c=0\\(x+\frac{b}{2})^2+c=(\frac{b}{2})^2\)

Answer 2

I have x^2-10x+25=144
x^2-10x+25-144=0
x^2-10x-119=0

from there on im kinda stuck to be honest. i dont even know if that first part is right

Answer 3

@zzr0ck3r

Answer 4

@jim_thompson5910

Answer 5

x^2-10x+25 factors to (x-5)(x-5) which is the same as (x-5)^2

Answer 6

so x^2-10x+25=144 turns into (x-5)^2=144

Answer 7

x= -7 or x=17