Please help! Medal And Fan! Will post equation below. I need to go to sleep but have been stumped on this for hours, hopefully someone can help me through the process while I sleep tonight. Thank you!!!

Question

anonymous · Answer

The one-to-one function f is defined below.

$$f(x)=\sqrt{5x-5}$$

Find f^-1, the inverse of f. Then give the domain of f^-1 using interval notation.

danjs · Answer

hi

danjs · Answer

to find the inverse of f(x) = y

swap x and y, then 
solve for y

danjs · Answer

x = sqrt(5y-5)

danjs · Answer

x^2 = 5y - 5

$$f ^{-1}(x)= \frac{ 1 }{ 5 }x ^{2} + 1$$

danjs · Answer

$$x \ge 0 $$ is  a restriction from the original function