OpenStudy (anonymous):

Evaluate f(1) using substitution: f(x)=2x^3-3x^2-18x+8

OpenStudy (anonymous):

@geerky42

OpenStudy (anonymous):

OpenStudy (geerky42):

Plug in 1. $f(\color{red}x) = 2\color{red}x^3 - 3\color{red}x^2-18\color{red}x+8\\~\\f(\color{red}1) = 2(\color{red}1)^3-3(\color{red}1)^2-18(\color{red}1)+8$

OpenStudy (anonymous):

i got -11, is that correct?

OpenStudy (anonymous):

@geerky42

OpenStudy (anonymous):

could you also possibly help me with these two questions too please

OpenStudy (anonymous):

OpenStudy (geerky42):

-11 ic correct

OpenStudy (anonymous):

ok great :)

OpenStudy (geerky42):

No idea about 6, but for \$5, just plug in 3 for x and 0 for P(x) and check if this equation is true or not. Make sense?

OpenStudy (anonymous):

so on like mathway graphing calculator is should plug 3 in for x and o for P(x)?

OpenStudy (geerky42):

Yeah, basically replace x with 3 and P(x) with 0, then see if equation is true

OpenStudy (anonymous):

which one is the P(x)?

OpenStudy (anonymous):

the 15(x) or is it something else

OpenStudy (anonymous):

3^3-7(3)^2+15(3)-9

OpenStudy (anonymous):

or is it something else?

OpenStudy (anonymous):

this is what the graph looks like @geerky42