How would I graph
f(x)=ln(x+4) and it's inverse f`(x)=e^x-4
I figured out the domain, range, and vertical aymptote but I don't understand how to graph it

Question

How would I graph 
f(x)=ln(x+4) and it's inverse f`(x)=e^x-4
I figured out the domain, range, and vertical aymptote but I don't understand how to graph it

perl · Answer

you want to graph the inverse?

perl · Answer

here are the two functions on the same graph https://www.desmos.com/calculator/74y7llqol0

anonymous · Answer

Why would they be crossing their axises at the -3's?

perl · Answer

lets call the inverse of f , g

f(x) = ln (x + 4)
g(x) = e^x - 4 

if you plug in x = 0 into  g(x) you get

g(0) = e^0 - 4 = 1 - 4 = -3

perl · Answer

it is because of the -4, the graph y = e^x is shifted down 4 units

perl · Answer

y = e^x ->  y = e^x - 4

anonymous · Answer

Is there a specific reason to use 0?

perl · Answer

you asked why does it cross the y axis at -3, the x value is zero when it crosses the y axis, thats why i plugged in x = 0