Question

solve the equation below for x: log2x+log(x-1)=log6x

Answer 1

recall :

Answer 2

\[10^{\log _{10}(x)} = x\]

Answer 3

Remember the rule: \(\log(a) + \log(b) = \log(ab)\)?

Answer 4

its B?

Answer 5

oh right

Answer 6

Combine your terms on the left hand side, \(\log(a) = \log(2x)\) and \(\log(b)=(x-1)\)

Answer 7

no

Answer 8

2x(x-1) = 6x

x = 0 or x = 4

Answer 9

\[\log(2x(x-1)) =\log(6x)\]\[10^{\large \log(2x(x-1))}= 10^{\large \log(6x)}\]\[2x(x-1) = 6x\]Now solve for x.

Answer 10

What do you get for your quadratic function?

Answer 11

x=0, x=4

Answer 12

\[2x^2 -6x-2=0\]Cansolve this by completing the square. Do you know how that method works?

Answer 13

One you do that, you can find your values of x. If they fit one of your answer choices, there you go :)