Question

What value of w does the system have no solution:
{3A + 5B = -12
wA - 15B = 6

Answer 1

you want to get it to the point where

the left side of the second equation, is a multiple of the left side of the first equation.

Answer 2

Like if your problem had a system of:
\(\large\color{black}{ 12Z+10Y=7 \\kZ -5Y=5 }\)

then:

\(\large\color{black}{ 12Z+10Y=7 \\-2(k)Z +10Y=-10 }\)

\(\large\color{black}{ -2(k)=12 }\)

\(\large\color{black}{ k=-6 }\)

Answer 3

And there, we will have when k=-6,
\(\large\color{black}{ 12Z+10Y=7 \\12Z +10Y=-10 }\)

Answer 4

and you see that THIS has no solution, right?

Answer 5

yes

Answer 6

Could you help me with this problem? Because i am confused...

Answer 7

I am trying, but I keep getting disconnected.

Answer 8

gotcha

Answer 9

\(\large\color{black}{ 3A + 5B = -12 \\ wA - 15B = 6 }\)

I'll set you up, lets divide the second equation by -3,
we get:

\(\large\color{black}{ 3A + 5B = -12 \\ (-\frac{1}{3})wA + 5B = -2 }\)

Answer 10

you now need to a value of w, for which (1/3)(w) is equal to 3

Answer 11

\(\large\color{black}{ (-\frac{1}{3})w=3 }\), then w=?

Answer 12

um...

Answer 13

I'm not sure

Answer 14

\(\large\color{black}{ (-\frac{1}{3})w=3 }\)

multiply both sides times -3, and tell me what w equals.

Answer 15

-9

Answer 16

w = -9

Answer 17

yes

Answer 18

So now what?

Answer 19

so, in order to make your system of equations,
\(\large\color{black}{ 3A + 5B = -12\\
wA - 15B = 63 }\)

have no solutions, \(\large\color{black}{w=-9 }\)

Answer 20

you are done:) this is it,.

Answer 21

okay! Cool! Thanks.

Answer 22

Not a problem!

Answer 23

Can you help me with this problem? Please?

Answer 24

@SolomonZelman

Answer 25

Let's see, I'll apload it, and do some labelling part:

Answer 26

https://www.desmos.com/calculator/yx3vavvpb3