A system of equations is shown below: -3x + 7y = -16 -9x + 5y = 16 Part A: Create an equivalent system of equations by replacing one equation with the sum of that equation and a multiple of the other. Show the steps to do this. (6 points) Part B: Show that the equivalent system has the same solution as the original system of equations. (4 points) @itsbribro @sammixboo @thomaster
im sorry i dont know
@dan815 @camerondoherty @Nnesha
@linn99123
@Skyz @KlOwNlOvE
I think it is asking for elimination multipply the first equation by -3 let me know what you get
-3(-3x + 7y = -16)
i dont know what you mean. like plug -3 into x and y?
naw just multiply it by everything
9x+(-21)y=48
okay and that negative will be negative 9x-21y=48 -9x+5y=16 now combine like terms by=c
what?
combine like terms with the 2 equations
-16y=64
then y=-4
okay now divide 64 by -16
yes now substitute -4 in for y in one of those equations
-9x+(-20)=16
now what
-9x-20=16 now solve for x
x=-4
@KlOwNlOvE now what
okay so x=-4 and y=-4
yes
okay so show how -9x-20=16 is equivalent to -9+5y=16
you mean -9x correct?
@camerondoherty @satellite73 can one of yall help him have a feeling i did it the wrong way and gtg
yes
idk how they are equivalent
I'm sure i led you in the wrong direction hopefully one of them will come help not real sure might have to substitute
they normally dont but okay.
i dougbt they will join
how do i do Part B: Ranga helped me on part a
Part A: -3x + 7y = -16 -9x + 5y = 16 Let us replace (2) by adding (2) to two times (1): 2 times (1): -6x + 14y = -32 Add (2): -9x + 5y = 16 -------------------- -15x + 19y = -16 So the second pair of equations are: -3x + 7y = -16 -15x + 19y = -16
okay now do what we did to the other system
what do you mean find x and y?
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