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The foci for the hyperbola
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@Samara8954 @Mendicant_Bias @Mertsj?
will you help me
no one will help me
@geerky42 @zuha ?
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@zephyr141 I think is True
@trishie10
i need to review my math. i don't know. sorry i couldn't help.
@ganeshie8?
it's true.
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\[\frac{\left( x-h \right)^2}{a^2}-\frac{\left( y-k \right)^2}{b^2}=1\]\[a^2+b^2=c^2\]the graph would be centered at (h,k) and then to find the distance the foci is from the center of the graph is\[c=\sqrt{a^2+b^2}\] and the foci would be\[(h-\sqrt{a^2+b^2},k)\]and\[(h+\sqrt{a^2+b^2},1)\]
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