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Mathematics 25 Online
OpenStudy (anonymous):

The foci for the hyperbola

OpenStudy (anonymous):

OpenStudy (anonymous):

@Samara8954 @Mendicant_Bias @Mertsj?

OpenStudy (samara8954):

will you help me

OpenStudy (samara8954):

no one will help me

OpenStudy (anonymous):

@geerky42 @zuha ?

OpenStudy (anonymous):

@zephyr141 I think is True

OpenStudy (anonymous):

@trishie10

OpenStudy (zephyr141):

i need to review my math. i don't know. sorry i couldn't help.

OpenStudy (anonymous):

@ganeshie8?

OpenStudy (zephyr141):

it's true.

OpenStudy (zephyr141):

\[\frac{\left( x-h \right)^2}{a^2}-\frac{\left( y-k \right)^2}{b^2}=1\]\[a^2+b^2=c^2\]the graph would be centered at (h,k) and then to find the distance the foci is from the center of the graph is\[c=\sqrt{a^2+b^2}\] and the foci would be\[(h-\sqrt{a^2+b^2},k)\]and\[(h+\sqrt{a^2+b^2},1)\]

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