Ask
your own question, for FREE!
Mathematics
20 Online
The foci for the hyperbola
Still Need Help?
Join the QuestionCove community and study together with friends!
@Samara8954 @Mendicant_Bias @Mertsj?
will you help me
no one will help me
@geerky42 @zuha ?
Still Need Help?
Join the QuestionCove community and study together with friends!
@zephyr141 I think is True
@trishie10
i need to review my math. i don't know. sorry i couldn't help.
@ganeshie8?
it's true.
Still Need Help?
Join the QuestionCove community and study together with friends!
\[\frac{\left( x-h \right)^2}{a^2}-\frac{\left( y-k \right)^2}{b^2}=1\]\[a^2+b^2=c^2\]the graph would be centered at (h,k) and then to find the distance the foci is from the center of the graph is\[c=\sqrt{a^2+b^2}\] and the foci would be\[(h-\sqrt{a^2+b^2},k)\]and\[(h+\sqrt{a^2+b^2},1)\]
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
VERNEISH:
Two objects are moving along separate linear paths where each path is described by position, d, and time, t.
Maci:
what are the best stock apps for people who want to start investing?
Twaylor:
genuienly how do i get better self control i keep watcing youtube and theres this
IzzyCookie:
|dw:1792074056138:dw| Uhm, I don't know where to ask this, but I'm in college welding at my community college, and I need help learning vertical welding for
thehearken:
not sure if this is considered spam, im sorry if it is, but does anyone have tips
13 hours ago
0 Replies
0 Medals
4 days ago
3 Replies
2 Medals
1 week ago
3 Replies
0 Medals
2 days ago
9 Replies
1 Medal
1 week ago
2 Replies
1 Medal