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OpenStudy (jhannybean):
\[x^3 +27 = 0\]subtract -27 from both sides of the equation first.
Take the cube root of both sides of the function.
You will find your answer.
OpenStudy (anonymous):
\[x^2+27=0\] one answer you get by thinking
the other two by factoring the sum of two cubes and using the quadratic formula for the second factor
OpenStudy (anonymous):
the answer is 3 then
OpenStudy (dtan5457):
the cube root of -27 is -3.
-3 times -3=9 times -3 again is -27.
OpenStudy (jhannybean):
Not just 3.
\(3 \cdot 3 \cdot 3 \ne -27\)
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OpenStudy (jhannybean):
@dtan5457 no answers.
OpenStudy (anonymous):
oh no solution
OpenStudy (jhannybean):
False.
OpenStudy (anonymous):
oh no
OpenStudy (anonymous):
you want a number that when cubed give you
\[\huge \color{red}-27\]
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OpenStudy (anonymous):
oh gotcha i got tht one but thrs more lol
OpenStudy (dtan5457):
^-1
OpenStudy (jhannybean):
Whereas multiplying it an even number of times will result in a positive answer: (-1)(-1)(-1)(-1)
OpenStudy (jhannybean):
Any time you multiply a negative an odd amount of times, you will end up with a negative answer, i.e (-1)(-1)(-1) =-1
OpenStudy (anonymous):
find the real solutions of x to the fourth plus 2x squared equals 5 using a graphing utility. round each solution to the nearest hundredth.
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OpenStudy (jhannybean):
Can you write out your function first?
OpenStudy (anonymous):
\[x ^{4} + 2x ^{3} = 5\]
OpenStudy (jhannybean):
Correction: \(x^4 +2x^2=5\)
OpenStudy (anonymous):
on my paper its 2x cubed
OpenStudy (jhannybean):
davidellis17
find the real solutions of x to the fourth plus 2x squared equals 5 using a graphing utility. round each solution to the nearest hundredth.
2 minutes ago
On here you hae written 2x squared, so that is why I corrected you.
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OpenStudy (jhannybean):
But ok, \(x^4 +2x^3=5\)
OpenStudy (anonymous):
oh srry bout tht
OpenStudy (jhannybean):
Pull out the LCM, between \(x^4\) and \(x^3\) which one would it be?
OpenStudy (anonymous):
3
OpenStudy (jhannybean):
Hmm... I'm not sure this function has any real solutions.
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OpenStudy (jhannybean):
@satellite73 ? A little help here.
OpenStudy (anonymous):
it would be so much easier if i had someone here lol
OpenStudy (anonymous):
what about \[20 -\frac{ x }{ c } = d\] solve for x
OpenStudy (fibonaccichick666):
so do you have a calculator?
OpenStudy (anonymous):
yes
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OpenStudy (fibonaccichick666):
what type?
OpenStudy (anonymous):
ti-30xa
OpenStudy (fibonaccichick666):
that's not a graphing calculator... darn
OpenStudy (fibonaccichick666):
ok so you have to do it the algebraic way instead of using a utility
OpenStudy (anonymous):
alright
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OpenStudy (fibonaccichick666):
\[ x^4+2x^3=5\] SO you have that, now what is the biggest number/variable expression you can pull out of BOTH \(x^4\) and \(2x^3\)?
OpenStudy (anonymous):
oh tht was a different prob but i guess x squared
OpenStudy (anonymous):
x cubed
OpenStudy (fibonaccichick666):
which is it xsquared or x cubed?
OpenStudy (anonymous):
x cubed lol
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OpenStudy (fibonaccichick666):
okee dokey so do you know what that looks like when you pull it out?
OpenStudy (fibonaccichick666):
can you "un"factor x^3?
OpenStudy (anonymous):
well prob x plus 2x = 5
OpenStudy (fibonaccichick666):
not quite,
OpenStudy (anonymous):
well im stuck
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OpenStudy (fibonaccichick666):
it will be \[x^3(x+2)=5\]
You cannot forget to write the whole equation, and what is x^3/x^3?
OpenStudy (anonymous):
graph \[y = \sqrt{x+5} -3\] find the domain and range