Question

Suppose a normal distribution has a mean of 38 and a standard deviation of 2. What is the probability that a data value is between 36 and 43?

Answer 1

U should ask hartnn this he is the best with math

Answer 2

First step is to determine the z-score for each data. Then look at your table that provides the probabilities of the z-scores to find the corresponding probabilities. Then subtract the probability of the smaller z-score from the probability of the larger z-score.

Answer 3

ok so i know that the z-score= x-myew/standard deviation, but do you know what the x would be? because then i get: z-score= x-38/2

Answer 4

You are given the x's in the question (36 and 43).

Answer 5

ohh so i use both separately ok thanks!

Answer 6

The x's are your data values.

Answer 7

so now i have 36-38/2= -1 and 43-38/2=5/2

Answer 8

Yes, you have to find the z-score for each data value (x). Follow the steps I laid out above.

Answer 9

ok, i found the z-score for -1= .1587 and z-score for 2.5=.9938
.9938- .1587= .8351

Answer 10

I don't have the table in front of me so I won't be able to verify your final answer, however if you follow the steps and perform the calculations and use the table properly, then you should be fine.

Answer 11

ok thanks!

Answer 12

Alright then GOOD LUCK!!