Question

The sum of 5 consecutive even numbers is 220.

What is the fourth number in this sequence?

Answer 1

5 consecutive number
let's right them like this
n+(n+1)+(n+2)+(n+3)+(n+4)=220
so 5n+10=220
solve for n

Answer 2

let numbers be x , x+1, x+2, x+3, x+4
then
x + x+1 + x+2 + x+3+ x + 4 = 220
find x

you require the value of x + 3

Answer 3

oh hold! i didn't pay attention to even

Answer 4

let's call the first number 2k
then we have 2k+ 2(k+1)+2(k+2)+2(k+3)+2(k+4)=220
solve for k

Answer 5

oops sorry i misread the question
even numbers

replace 1, 2, 3 and 4 by 2, 4 , 6 and 8

you require the value of x + 6

Answer 6

@iGreen

Answer 7

you have 10k+20=220
k=200/10
k=20
the first number is
40, 42, 44, 46, 48
if we add all this number together we get 220
then the fourth number is 46