Question

simplify: [(n+1)!/n!]-n

Answer 1

\[(n+1)!=(n+1)\times n!\]

Answer 2

(n+1!/(n-1)! = (n+1)*n*(n-1)(n-2).../(n-1)*(n-2)... = (n+1)n OR n(n+1)

Whenever doing division problems with factorials,always look for the

results of cancelation of terms in the numerator by those in the denominator.

Answer 3

does that help:)

Answer 4

still a bit confused :/