Question

log8 x 56

Answer 1

@SolomonZelman

Answer 2

I mean all real numbers less than 0

Answer 3

gonna have to clarify the function for us

Answer 4

as is, it is bad at x=0

Answer 5

the range of the function would be the domain of the inverse ...

solve the equation for x in terms of y and determine what y values are acceptable

Answer 6

the function is the numbers...

Answer 7

y = -24/x^2 + 8

y-8 = -24/x^2

x^2 = -24/(y-8)

x = +- sqrt(-24/(y-8))

Answer 8

so the domain of the inverse is such that:

-24/(y-8) > 0

and y-8 \(\ne\) 0

Answer 9

All real numbers greater than or equal to -3 but less than 0 then......?

Answer 10

\[y=\frac{-24}{x^2}+8 \text{ or } y=\frac{-24}{x^2+8}\]

Answer 11

but that's not describing it....

Answer 12

if y-8 < 0 then -24/-k > 0

assuming ive read it correctly :)

Answer 13

what you said earlier makes more sense for
\[y=\frac{-24}{x^2+8 } \text{ and not } y=\frac{-24}{x^2}+8\]

Answer 14

@KierseyClemons

Answer 15

y = -24/x^2 + 8 is NOT same as y = -24/(x^2+8)

you need to use parenthesis if your function is \(y = \dfrac{-24}{x^2+8}\)

Answer 16

Notice that the function is always negative
so 0 is a natural upperbound for the function