Question

I was supposed to solve for z and im not sure if im doing this right.

Answer 1

\[a^2 + b^2 = c^2?\]

Answer 2

yeah I did all of that and I got stuck at
64 + 196=c^2

Answer 3

add and take the square root

Answer 4

64+196=260
160=c^2
Now we take the square root on both sides

\[\sqrt{260}=\sqrt{c^2}\]
\[\sqrt{260}=c\]

Answer 5

Thanks

Answer 6

well we can simplify sqrt 260 to
\[\sqrt{260}=\sqrt{4*65}=2 \sqrt{65}\]