Question

Honors Algebra 2

Answer 1

\[3\sqrt[5]{(x+2)^3}+3=27\]

Answer 2

\[\sqrt[5]{(x+2)^2}=8\]

That's as far as I got

Answer 3

first subtract -3 from both sides.\[3\sqrt[5]{(x+2)^3} = 27-3\]

Answer 4

whoops! The ^2 is supposed to be ^3

Answer 5

that's what I got. then I divided by 3 to get 8.

Answer 6

Alright.

Answer 7

\(\sqrt[5]{(x+2)^3} = 24\)

don't I then do ^5 to both sides?

Answer 8

You raise each side by the power of 5*

Answer 9

No no, you subtracted 27 - 3 = 24 /3 = 8, that was correct.

Answer 10

\[\large \left(\sqrt[5]{(x+2)^3}\right)^5 = (24)^5\]This will help eliminate the 5th root.

Answer 11

\((x+2)^3 = 32768\)


you forgot to divide by 3...

Answer 12

I have it done, I just want to make sure it was correct....then I cbrt it to get x+2=32
x then equals 30, correct?

Answer 13

Oh yes, my mistake. \[\large \left(\sqrt[5]{(x+2)^3}\right)^5 = (8)^5\]That was what I meant to write there.

Answer 14

okay :) just making sure :D

Answer 15

Now take the cube root of both sides. :)\[\large \sqrt[3]{(x+2)^3} = \sqrt[3]{8^5}\]

Answer 16

You can write it either way, \(8^5 \implies 32768\)

Answer 17

okay

Answer 18

So what does the right side of your equation become when simplified?

Answer 19

32, right?

Answer 20

so x+2=32?

Answer 21

Yes :) and the left side simply becomes \((x+2)\)

Answer 22

Okay, so I got it right. Thank you!

Answer 23

Now you can solve for x by subtracting -2 from both sides :)

Answer 24

Awesome!