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Mathematics 20 Online
OpenStudy (anonymous):

How many solutions does the equation have http://static.k12.com/bank_packages/files/media/mathml_edb583a3562463eeb3d6c0b27ea5a96ea9da0163_1.gif

OpenStudy (danjs):

4x + 2x - 6 = 8x + 12 can you do the next step?

OpenStudy (anonymous):

umm i really have no clue

OpenStudy (danjs):

all i did was distribute 2(x - 3) = 2x - 6

OpenStudy (danjs):

so you have to combine your x terms together now 2x + 4x = 6x

OpenStudy (anonymous):

ok

OpenStudy (danjs):

6x - 6 = 8x + 12 ---->take away 6x from both sides -6 = 2x + 12 ----- take away 12 from both sides -18 = 2x divide by 2 on both sides -9 = x

OpenStudy (danjs):

how many solutions?

OpenStudy (anonymous):

1

OpenStudy (danjs):

right, If you get x = some number, that is 1 solution If you get a false statement like 5 = 12, then zero solutions if you get a true statement like 5 = 5,. then you have an infinite number of solutions.

OpenStudy (anonymous):

cool ! (:

OpenStudy (anonymous):

help with one more i promise xD sorry

OpenStudy (danjs):

k

OpenStudy (anonymous):

its 8+2 (8x -6 ) =

OpenStudy (danjs):

ok using the rules i wrote above, first distribute out the given part of the equation 8 + 16x - 12 =

OpenStudy (anonymous):

Choose exactly two answers that are correct. A. 2(4x + 7) B. 9x – 10 C. 16x – 4 D. 4(4x – 1)

OpenStudy (anonymous):

okay

OpenStudy (danjs):

what you want is a true statement, like 5x + 5 = 5x + 5,

OpenStudy (danjs):

so from the given, 8 + 16x - 12 add the numbers first 16x - 4 Now factor out a common 4 from each of those terms to get... 4(4x -1)

OpenStudy (anonymous):

4(4x-1) ?

OpenStudy (danjs):

that gives you two answers

OpenStudy (anonymous):

okay (: how do i find the other one

OpenStudy (danjs):

it was the first step i did, all you do is add the numbers and get 16x - 4

OpenStudy (anonymous):

oooohhh xD youre amazing thanksss

OpenStudy (danjs):

16x - 4 = 16 x - 4 -4 = -4 true, and recall the rule, TRUE means infinite solutions

OpenStudy (anonymous):

ohh okay

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