Question

in java how can one check if there are spaces after a char?

Answer 1

Well, how is it being stored or taken in?

Answer 2

i am trying to check if an input has that char but it will only count it if there are no spaces afterwards

Answer 3

i am doing a tweet tester, checking if there are # but it will only count the # if there are no ' ' after or no '\t'

Answer 4

You can do a regex.

Answer 5

i dont know what that is :(

Answer 6

Regular Expressions. They can match white space.
http://docs.oracle.com/javase/tutorial/essential/regex/pre_char_classes.html

Answer 7

If you're using characters as your data type, then there won't be any spaces after it so you might want to consider this as a way to check.

Here's a super silly way to do it based off this with spaces

```
String cStr = "c";
char[] cAndSpaces = cStr.toCharArray();
char c = cAndSpaces[0];
```

So I made a string with c and spaces after it. Then I used the String method toCharArray() to create an array. Then I used the first element, which in arrays is the zeroth element I guess you can call it, which is in the array. A quicker way would be

```
String cStr = "c";
char c = cStr.toCharArray()[0];
```

Another possible way to do it is check the length of the string.

```
String cStr = "c";
if (cStr.length() == 1){
System.out.println("no spaces!");
}
```

I'm almost sure neither of these are going to help you directly since your question is too vague, but maybe it will help to think about it.

Answer 8

this is my code
import java.util.Scanner;

class tbesting
{
public static void main(String[] args)
{
Scanner scan = new Scanner (System.in);
System.out.println("Please enter a tweet: ");
String input = scan.nextLine();
int length = input.length();
int count = 0;
int hashtags = 0, attributions = 0, links = 0;
char letter;
boolean tf;
char s = ' ';
char t = '\t';
String linkss = "http://";
if (length > 140)
{
System.out.println("Excess characters: " + (length - 140));
}

else
{
while (count < length)
{
letter = input.charAt(count);

{

if ((letter =='#') && (letter + 1!= '\t') && (letter + 1!= ' '))
{
hashtags ++;
count ++;
}
}
if (letter == '@' && letter + 1 != ' ' && letter + 1 != '\t')
{
attributions ++;
count ++;
}

if (letter == 'h')
{
// String test = input.substring(count,count+6);
// test = test.toLowerCase();
if (input.toLowerCase().contains(linkss.toLowerCase()))
// boolean link = input.equalsIgnoreCase(linkss);
// if (input.startsWith("http://", count)|| link == true)
{
links ++;
count++;
}
else
{
count++;
}
}
else
{
count ++;
}
}
System.out.println("Length Correct");
System.out.println("Number of Hashtags: " + hashtags);
System.out.println("Number of Attributions: " + attributions);
System.out.println("Number of Links: " + links);
}
}
}

Answer 9

The problem is you need to be sure that there is even is a next char before finding out what that next char is.

Answer 10

In your case though, you are using `letter + 1` when you mean to say `input.charAt(count+1)`.

Answer 11

You should check that `count+1<length` as well.