Question

Please help, I need a simpler way of solving this.

Answer 1

\[find~~ab+5(a-b) ~~where ~~a=\log _{12} ~~and~~ b=\log _{24}54\]

Answer 2

@Kainui

Answer 3

\[a=\log_{12}? \]

Answer 4

@ParthKohli @paki

Answer 5

@ganeshie8 @iambatman

Answer 6

@EmmaTassone yea that's what a ='s.

Answer 7

DANG! I meant \[a=\log _{12}18\]

Answer 8

looks tricky but wolfram says it equals 1
http://www.wolframalpha.com/input/?i=log%2818%29%2Flog%2812%29*log%2854%29%2Flog%2824%29+%2B+5%28log%2818%29%2Flog%2812%29-log%2854%29%2Flog%2824%29%29

Answer 9

O_O THANK YOU!!!!!!!

Answer 10

Oh you're just looking for answer ha!

Answer 11

Nah. I need to show work. My teachers motto is "No work. No credit!"

Answer 12

\[ab+5(a-b)= \log_{12}18.\log_{24}54 +5(\log_{12}18-\log_{24}54) =\frac{ \log_{10}18 }{ \log_{10} 12}.\frac{ \log_{10}54 }{ \log_{10} 24}+5(\frac{ \log_{10}18 }{ \log_{10}12 } -\frac{ \log_{10}54 }{ \log_{10}24 })\]
and you can use calculator from here.