HELP!!! someone? Explain this to me please! Suppose a house that costs $270,000 appreciates by 5% each year. In about how many years will the house be worth $350,000? Use the equation 350 = (270)(1.05)x and round the value of x to the nearest year. 5 4 6 7
So we have an exponential equation:\[\Large\rm A=P(b)^x\]Where P is the principle. (Starting amount). We assume the house will be worth 350 (thousand) at some point, so we let our A be that amount. b represents the growth rate.\[\Large\rm 350=270(1.05)^x\]To solve for x we'll need to use logarithms.
Let's start by dividing each side by 270,\[\Large\rm \frac{350}{270}=1.05^x\]
So itll be 1.29= 1.05^x
1.30 is probably a better way to round that.
True
Next, we'll take the log of each side (log base 10 is fine),\[\Large\rm \log(1.30)=\log(1.05^x)\]
0.1139=log(1.05^x)
The log is helpful for getting variables out of the exponent position.
Hmm but my calculator doesnt register x as a exponent
Here is the log rule that will help us:\[\Large\rm \log(a^\color{orangered}{x})=\color{orangered}{x} \log(a)\]
We're not up to the calculator step yet ;)
Oh okay! so it would look like 0.1139=xlog(1.05)
Mmm good good good. Just a few more steps to finish it up from there.
Okays :D
It seems like you prefer to carry the decimals around, rather than the logs. So from here, let's get our decimal approximation for log(1.05)
its 0.0211
0.1139=0.0211x ok good. last step? :d any ideas?
divide 0.1139 by 0.0211= 5.39 = 5.4
so 5?
yay good job \c:/
Yay! thank you so much! :)
np :3
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