Question

If 2x^2 +kx-12 is dividible by (x-k) where k is a constant, then find the two values of k

Answer 1

@SolomonZelman @jim_thompson5910

Answer 2

(x-k) must be a factor of 2x^2+kx+12

Answer 3

use a quadratic formula to solve for k

Answer 4

If P(x) = 2x^2 +kx-12 and P(x) is divisible by x-k, then P(k) = 0.

Answer 5

@jim_thompson5910 can u elaborate

Answer 6

If P(x) = 2x^2 +kx-12, then what is P(k) equal to?

Answer 7

i m not sure

Answer 8

why not replace every x with k and see what happens

Answer 9

that's what P(k) is telling you to do

Answer 10

oh right

Answer 11

k = 2?

Answer 12

there's one more solution

Answer 13

one of your steps should be 3k^2 - 12 = 0