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Mathematics 22 Online
OpenStudy (anonymous):

New one

OpenStudy (anonymous):

OpenStudy (solomonzelman):

you can already see the first term, right?

OpenStudy (anonymous):

-6

OpenStudy (solomonzelman):

yes

OpenStudy (anonymous):

ok

OpenStudy (solomonzelman):

and then: plug in 4 for n, to find \(\large\color{black}{ a_4 }\) (the 4th term)

OpenStudy (anonymous):

18

OpenStudy (solomonzelman):

now quite: \(\large\color{blue}{ a_n=-6+(n-1)6 }\) \(\large\color{blue}{ a_4=-6+(4-1)6 }\) \(\large\color{blue}{ a_4=-6+(3)6 }\) \(\large\color{blue}{ a_4=? }\)

OpenStudy (anonymous):

negative 6??

OpenStudy (solomonzelman):

\(\large\color{blue}{ a_4=-6+(3)6 }\) \(\large\color{blue}{ a_4=-6+18 }\) \(\large\color{blue}{ a_4=? }\)

OpenStudy (anonymous):

Its A

OpenStudy (solomonzelman):

yup, there it is! that's right;)

OpenStudy (anonymous):

Thank you!

OpenStudy (solomonzelman):

yw

OpenStudy (anonymous):

Haha i found a easy way to do it!

OpenStudy (solomonzelman):

that's nice to hear.

OpenStudy (anonymous):

Thank you again

OpenStudy (solomonzelman):

yw

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