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you can already see the first term, right?
-6
yes
ok
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and then: plug in 4 for n, to find \(\large\color{black}{ a_4 }\) (the 4th term)
18
now quite: \(\large\color{blue}{ a_n=-6+(n-1)6 }\) \(\large\color{blue}{ a_4=-6+(4-1)6 }\) \(\large\color{blue}{ a_4=-6+(3)6 }\) \(\large\color{blue}{ a_4=? }\)
negative 6??
\(\large\color{blue}{ a_4=-6+(3)6 }\) \(\large\color{blue}{ a_4=-6+18 }\) \(\large\color{blue}{ a_4=? }\)
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Its A
yup, there it is! that's right;)
Thank you!
yw
Haha i found a easy way to do it!
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that's nice to hear.
Thank you again
yw
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