4n3 + 5n2 + 6n + 15 factors to (3n2 + 2) (3n + 5).

True
False

Question

4n3 + 5n2 + 6n + 15 factors to (3n2 + 2) (3n + 5).
 	
	True
	False

hartnn · Answer

what do u think ?

anonymous · Answer

i think its false

hartnn · Answer

hint : compare the constants for both expressions!
for 4n3 + 5n2 + 6n + 15 its 15

for  (3n2 + 2) (3n + 5).
what is it?

and why do you think its false ?

anonymous · Answer

the 4n3 and 5n2 wont factor into the expression i dont think

hartnn · Answer

if you factor out n^2 from that you get (4n+5)
which is NOT mentioned as one of the factors,
so in a way, you're correct :)
Its false!

anonymous · Answer

ok thank you :)

hartnn · Answer

what i suggested is to compare constants for both expression,

for 4n3 + 5n2 + 6n + 15 its 15

for  (3n2 + 2) (3n + 5).
it is 2*5 =10

since constants are not same, they can't be equal
hence false :)

hartnn · Answer

welcome ^_^

demonchild99 · Answer

$\cal\color{purple}{Welcome~to~Openstudy!!!!}$