Question

One more rational expression before I sleep..

Answer 1

\[(y^0+3y^{-2})^3\]

Answer 2

Evaluate when y=2

Answer 3

substitute y=-2 into the equation @dtan5457

Answer 4

I ended up with 21/4 which isn't right..

2^0=1

3(2)^-2=3/4

1+3/4=1 3/4

(1 3/4)^3

1 3/4=7/4

7/4 times 3/1=21/4

Answer 5

which part i do wrong?

Answer 6

replace y by 2
-2 i guess typo :D

Answer 7

yes, it is y=2

Answer 8

anyone see my error?

Answer 9

lol bout to see the stupid error i made

Answer 10

\(1+3/4=1 3/4--------wrong\)

\(1+3/4=(4/4)+ 3/4--------right\\
=7/4\)

Answer 11

well like we did last question should move 2^-2 at the bottom first

Answer 12

i had 7/4 though

Answer 13

u should not use mixed fractions

Answer 14

to cube 7/4 i did 7/4 times 3/1

Answer 15

21/4??