Prove Ptolemy's Theorem through Algebra only
@Directrix @jim_thompson5910
take a look here http://www.cut-the-knot.org/Curriculum/Geometry/HingedPtolemy.shtml
it doesn't work and it isn't exactly all algebra
There is a nice one here with sines and cosines http://www.cut-the-knot.org/proofs/sine_cosine.shtml
that whole site is pretty good, take a look around
im not allowed to use trig sorry
This one is good too, By Inversion http://www.cut-the-knot.org/proofs/PtolemyByInversion.shtml
@DanJS I said I cant use trig and anything over year 8
here is a simple one, scroll down to where it says proof, it is just by similar triangles http://www.cut-the-knot.org/proofs/ptolemy.shtml
@DanJS I said im ONLY allowed to use ALGEBRA
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On the diagonal BD locate a point M such that angles ACB and MCD be equal. Since angles BAC and BDC subtend the same arc, they are equal. Therefore, triangles ABC and DMC are similar. Thus we get CD/MD = AC/AB, or AB·CD = AC·MD. Now, angles BCM and ACD are also equal; so triangles BCM and ACD are similar which leads to BC/BM = AC/AD, or BC·AD = AC·BM. Summing up the two identities we obtain AB·CD + BC·AD = AC·MD + AC·BM = AC·BD
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that is just algebra, not sure if you can use that one
asi in im not supposed to use angles and similarity etc.
@TuringTest can u help
hmm, sorry i really dont know any simpler one... here is one other i found that may help, it uses angles though http://www.trans4mind.com/personal_development/mathematics/geometry/ptolemy_theorem.htm
yeah, i cant think of a proof that doesnt involve similar triangles. ... http://planetmath.org/ProofOfPtolemysTheorem Same as last one, just simpler
good luck
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