Question

Help with a calculus question!

Answer 1

can i see the link how you put it into wolfram?

Answer 2

I would have done this:
\[\text{ let } g(x)=\sqrt{1+x^2} \\ F(x)=G(1)-G(x) \text{ where } G'=g \\ \\ \text{ then differentiate both sides } \\ \]
then plug in 1 for x

Answer 3

i just got out of it but ill do it again

Answer 4

oh wait, now i got -sqrt of 2

Answer 5

that sounds better
are you just suppose to use a calculator to evaluate this?

Answer 6

like you don't need to know how to do without one?

Answer 7

yess it says it in the question

Answer 8

yeah i think that would be the next lesson(:

Answer 9

do you know this
\[\int\limits_{}^{}g(t) dt=G(t)+C\]
Where G'=g
\[F(x)=\int\limits_{x}^{1}g(t) dt=G(t)|^1_x=G(1)-G(x)\]

Answer 10

\[\text{differenatiating both sides of } F(x)=G(1)-G(x) \text{ gives } F'(x)=[G(1)-G(x)]' \\ F'(x)=[G(1)]'-[G(x)]'\]
But guess what G(1) is just a constant
and the derivative of a constant is ?