Question

Solve the equation for x:
x+4 = sqrt(8-x)

Answer 1

Square both sides of the equation first.

Answer 2

(x+4)^2=8-x

Answer 3

x^2+8x+16=8-x

Answer 4

\[(x+4)^2 = (\sqrt{8-x})^2\]

Answer 5

x^2+9x+8=0

Answer 6

do you know quadratic formula? @nlom

Answer 7

You don't need it.

Answer 8

hmm yeah

Answer 9

Fidn two numebrs that add to give you 9, and multiply to give you 8.

Answer 10

\[x+4=\sqrt{8-x}\]
\[8-x \ge0,8\ge x ~or~x \le 8.\]
squaring
\[\left( x+4 \right)^2=8-x\]
\[x^2+8x+16-8+x=0\]
\[x^2+9x+8=0\]
find x by quadratic formula or by making factors.

Answer 11

@nlon , you need to participate on your post.

Answer 12

@nlom

Answer 13

(-9+-sqrt(81-32))/2

Answer 14

(-9+-7)/2

Answer 15

tell me what you get

Answer 16

From squaring both sides I got x^2 + 16 = 8-x ?

Answer 17

no

Answer 18

(a+b)^2=a^2+2ab+b^2

Answer 19

Thanks!

Answer 20

np