Question

@DanJS

Answer 1

hii can you explain each step of this? @Michele_Laino was explaining it, but was doing the completely wrong thing haha

Answer 2

ill try. lol

Answer 3

@freckles please explain

Answer 4

explain what?

Answer 5

the problem...........

Answer 6

i don't see any problems here. lol

Answer 7

oops it didnt go through, i refreshed my page and it wasnt there haha

Answer 8

@DanJS

Answer 9

yeah the thing is lagging like crazy today

Answer 10

okay good so its not just me hahah

Answer 11

yeah, i remember the cooling law from differential equations class..

Answer 12

need to integrate to get the function of temperature

Answer 13

\[\frac{ dT }{ dt } = k(T-T _{e})\]
\[\frac{ 1 }{ T - T _{e} }dT = k*dt\]

Answer 14

Integrating both sides of that gives... Te is the 38 degrees by the way

Answer 15

\[\ln(T-T _{e}) = k*t + C\]

\[T - T _{e} = C*e ^{k*t}\]

Answer 16

\[T(t) = T _{e} + C*e ^{k*t}\]

There is the function for Temperature at time t, with the initial temp of Te

Answer 17

what lol

Answer 18

For this prob Te = 38

It is the same thingyou have in your integration, just solved for T(t)

Answer 19

nevermind, can you go to the one i tagged you in, i already got that haha

Answer 20

\[T(t) = 38 + C*e ^{kt}\]

Answer 21

well there is the function for this prob, you need to use the other data points in the problem T(0), and so on, to find the values for C and k.

Answer 22

Lol i busted out an old HW for doing this