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Mathematics 19 Online
OpenStudy (mindblast3r):

Help please :)

OpenStudy (mindblast3r):

writing my question.

OpenStudy (mindblast3r):

\[\frac{ 1 }{ -2 }\times\frac{ 1 }{ -2 }\times\frac{ 1 }{ -2 }\times\frac{ 1 }{ -2 }\]

OpenStudy (mindblast3r):

\[-(\frac{ 1 }{ 2 })^4\]

OpenStudy (mindblast3r):

are these equal?

OpenStudy (mindblast3r):

well i already know they are not equal but i'm not sure why.

hartnn (hartnn):

what do you think ? \(\Large -1\times -1 =1\)

OpenStudy (mindblast3r):

this is correct

hartnn (hartnn):

even number of negatives multiply to give out a positive

hartnn (hartnn):

odd number of negatives multiply to give out a negative

OpenStudy (anonymous):

\[\frac{ 1 }{ -2 }\times\frac{ 1 }{ -2 }\times\frac{ 1 }{ -2 }\times\frac{ 1 }{ -2 } = \dfrac{1}{(-2)^4}\]

hartnn (hartnn):

oh yeah, it was \(\huge -2\) which was mutiplied 4 times so \(-2\) will have the exponent of 4

OpenStudy (anonymous):

\[-\left(\dfrac{1}{2}\right)^4 = -\left[\dfrac{1}{2}\times\dfrac{1}{2}\times\dfrac{1}{2}\times\dfrac{1}{2}\right] = \dfrac{1}{-(2)^4}\]

OpenStudy (mindblast3r):

\[-(\frac{ 1 }{ 2 })^4\]

OpenStudy (anonymous):

Notice that negative sign is outside of parentheses.

OpenStudy (mindblast3r):

yes

hartnn (hartnn):

\((-a)\times (-a) = (-a)^2 \ne -a^2\)

OpenStudy (anonymous):

So tell me \(\dfrac{1}{(-2)^4} = \dfrac{1}{-(2)^4}\)?

OpenStudy (mindblast3r):

how aren't they equal?? I don't get it.

OpenStudy (mindblast3r):

you distrubute the negative sign to the #2

OpenStudy (anonymous):

I mean is it true that \(\dfrac{1}{(-2)^4} = \dfrac{1}{-(2)^4}\)?

OpenStudy (mindblast3r):

correct?

OpenStudy (mindblast3r):

it looks true to me.

OpenStudy (mindblast3r):

oh wait.

OpenStudy (mindblast3r):

i must be doing something wrong.

hartnn (hartnn):

\(\large (-a)\times (-a) = =-1\times a \times -1\times a =a^2 \\ -a^2 = -1\times a \times a =-a^2\)

OpenStudy (anonymous):

\((-2)^4 = -2\times-2\times-2\times-2 \neq -2\times2\times2\times2 = -(2)^4\)

OpenStudy (anonymous):

Another way to look at it is that \(-2 = -1\cdot2\), so \((-2)^4 = (-1)^4\cdot2^4\)

OpenStudy (mindblast3r):

i'm thinking guys, thanks a lot for helping me :)

OpenStudy (mindblast3r):

oh i think i get it now.

OpenStudy (mindblast3r):

it's just about brackets, exponents, multiplication, addition, subtraction, BEDMAS.

OpenStudy (mindblast3r):

\[-(2)^4 \neq (-2)^4\]

OpenStudy (mindblast3r):

correct??

hartnn (hartnn):

yes

OpenStudy (mindblast3r):

because,

hartnn (hartnn):

\((-2)^4= (-2)\times (-2)\times (-2)\times (-2) = 4\times 4 =16 \\ -(2^4) = -(2\times 2\times 2\times 2 ) = - (4\times 4) = -16 \)

OpenStudy (mindblast3r):

\[-2^4 =-2\times-2\times-2\times-2 = 16\]

OpenStudy (mindblast3r):

lol yes, you beat me to it.

hartnn (hartnn):

but you're forgetting the brackets :P

hartnn (hartnn):

\((-2)^4 =... =16\)

OpenStudy (mindblast3r):

omg i love you <3

hartnn (hartnn):

I <3 you too ;)

OpenStudy (mindblast3r):

thank you very much :D

OpenStudy (mindblast3r):

bye for now :)

hartnn (hartnn):

welcome ^_^

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