Question

Anyone up for some simple Algebra? :)

Answer 1

Simplify f(x) = x^2 - (x+1)(x-1)

Answer 2

sure:
You can use a difference of squares for the \({\color{blak}{ {(x+1)(x-1)} }}\).
Just like: \({\color{blue}{ {(a+b)(a-b)=a^2-b^2} }}\)
So is, \({\color{black}{ {(x+1)(x-1)=x^2-1^2} }}\) which is simplified to: \({\color{black}{ {(x+1)(x-1)=x^2-1} }}\)
(because \({\color{black}{ {1^2} }}\) is just \({\color{black}{ {1} }}\))

So this is what happening at the first step:
\({\color{black}{ {x^2 - (x+1)(x-1)} }}\)
now becomes,

\({\color{black}{ {x^2 - x^2-1} }}\)

Answer 3

then you tell me what cancels out. on you to finish the problem

Answer 4

f(x) = -1 then? :D that's what I got when I did it with pen and paper but it looked to simple to be right xD thank you!

Answer 5

too*