How many solutions are there to the following system of equations? 2x + 6y = 4 5x + 15y = 10 A. 0 B. 1 C. infinitely many D. 2
\(\large\color{blue}{ 2x + 6y = 4}\) \(\large\color{blue}{ 5x + 15y = 10}\) divide the first equation by 2, and the second equation by 5
Like this? 2x + 6y divided into 2?
Will the first one be 1x + 3y = 3 ?
\(\large\color{blue}{ 2x ~~+~~ 6y ~~= ~~4}\) \(\large\color{blue}{ \Downarrow}\) \(\large\color{blue}{ \Downarrow}\) \(\large\color{blue}{ \Downarrow}\) \(\large\color{blue}{ \div2}\) \(\large\color{blue}{ \div2}\) \(\large\color{blue}{ \div2}\) \(\large\color{purple}{ x ~~+~~ 3y ~~= ~~2}\)
do the same division, but by 5, for the second equation.
Ah-ha! :) Okay, thanks! Let me try to do the second one.
yes, go ahead:)
@SolomonZelman The second equation is: 2.5x + 7.5y = 5
you are dividing by 5, not by 2
Right! I forgot. :( The answer is: 1x + 3y = 2
if the equations are the same, then there is infinitely many solutions
yes
@SolomonZelman What do we do now?
Oh, I had not noticed that they had the same equations!
\(\large\color{purple}{x+3y=2}\), this is what both of your equations came to be equal to, right?
Right.
Oh, you get it, i c....
\(\large\color{purple}{x+3y=2}\) \(\large\color{purple}{^{^{\Huge-}}~~x+3y=2}\) \(\large\color{purple}{^{\text{______________}}}\) \(\large\color{blue}{0=0}\)
how many solutions are there?
oh 0=0 is true for any x value, correct?
There are no solutions.
I think.
your system, after your divisions that we performed, is: \(\large\color{purple}{x+3y=2}\) \(\large\color{purple}{x+3y=2}\) \(\large\color{purple}{x=2-3y}\) \(\large\color{purple}{x=2-3y}\) \(\large\color{purple}{x=x}\)
x=x has infinitely many solutions.
When ever you have 2 equations that are multiples of each other (and here we do so too, as we have showed), that means infinity of solutions.
Oh, I think that I understand a little bit better now. :)
|dw:1420678078450:dw|
two lines on top of each other, they will intersect infinite times
And so our answer is C. infinitely many.
yup
Well, thank you for your help and time. I have three more questions, so if I need help can I tag you to the question(s)? @SolomonZelman
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