Question

I NEED HELP ASAP! MEDAL, FAN!
what would a cosine function look like with a given amplitude of 7, period of pi/6, no horizontal shift, and vertical shift of down 2?

Answer 1

what do u need help with @countrywhitegirl1997

Answer 2

answering the question above! also trhe hint for it is :f(x)= a cos(bx+c)+d

Answer 3

the hint is the formula u r supost to use

Answer 4

okay, well i dont know how to do it! D: I am studying and i need it kind of fast, i am doing a test with my teacher soon!

Answer 5

oh okay

Answer 6

hank on brb

Answer 7

okay thank you.

Answer 8

welcome

Answer 9

wow this is hard

Answer 10

can you just try your best?

Answer 11

im trying to watch a 3 month old as i am doing this study guide. please i need you help.

Answer 12

hi

Answer 13

if you are still there we can do this quickly
let me know

Answer 14

hey, you can help me?

Answer 15

yeah sure in like 3 easy steps

Answer 16

\[y=a\cos(bx)+c\] amplitude is 7 so
\[y=7\cos(bx)+c\]

Answer 17

vertical shift down 2 so
\[y=7\cos(bx)-2\]

Answer 18

period is \(\frac{\pi}{6}\) is the only part that requires algebra

Answer 19

period is \(\frac{2\pi}{b}\) we need to find \(b\) so solve
\[\frac{2\pi}{b}=\frac{\pi}{6}\]for \(b\)

Answer 20

if you do that carefully (just do it without the \(\pi\) you should get \(b=12\)
final answer
\[y=7\cos(12x)-2\]

Answer 21

@countrywhitegirl1997 that wasn't too bad was it?

Answer 22

omg thank you so so so much! (: and no it wasnt.

Answer 23

lol you are welcome :)

Answer 24

@misty1212 can you help me with a few more?

Answer 25

sure i got a couple minutes

Answer 26

okay well the next one i need help with it: How are the special right triangle identities used to find the coordinate points around the unit circle?

Answer 27

@misty1212

Answer 28

@misty1212 how do you get 12 when solving for b? i just dont get that step