HELP? I'm so so stuck on this simple question, I think i'm overthinking it. How do I graph y=50x + 200? I know that this equation is in slope-intercept form (y= mx+b) and m is the slope and b is the y-intercept. But, whenever i plug in the numbers and try to plot the equation, what i'm getting doesn't seem to represent y= 50x + 200.

Question

misty1212 · Answer

hi!
the scale might be funny

misty1212 · Answer

it is just what you said it was

misty1212 · Answer

http://www.wolframalpha.com/input/?i=y%3D+50x+%2B+200

misty1212 · Answer

y intercept is 200
slope is 50

anonymous · Answer

Hi, thanks for your reply. I'm being told to graph a line representing a real-life concept. This is the graph. I plotted a point on 200 for the y-intercept, but i don't know where to plot the other point on the x-intercept

misty1212 · Answer

start at $(0,200)$ the go over one step up 50 
but the 50 is just one box on the y, do it wil look like you are going up one step

anonymous · Answer

y=200 Is it multiple choice?

misty1212 · Answer

|dw:1420860920510:dw|

misty1212 · Answer

it is going to look like the line has slope one
over one, up one 
but the slope will actually be 50 because of the units on the y axis

anonymous · Answer

Ohhhh, ok, i'm starting to understand it now. I thought i plotted the points something like this, then draw a line through it.

misty1212 · Answer

oh no not like that, like the one i wrote 
you got that?

anonymous · Answer

Yea, it makes a lot more sense since i am graphing a line based on a real-life concept. Thank you so much!