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Mathematics 19 Online
OpenStudy (anonymous):

Help? Triangle ABC has AC = BC, and ∠ACB = 96°. D is a point in triangle ABC such that ∠DAB = 18° and ∠DAB = 30°. What is the measure (in degrees) of ∠ACD?

OpenStudy (anonymous):

anyone?

OpenStudy (bohotness):

We know, by the 1800-Triangle Theorem, angle ADB = 132 degrees. From addition addition, we also know: angle CAD = 24 degrees angle CBD = 12 degrees It appears we have four unknowns, the angles labeled a, b, c, and d. We know 1) at vertex C a + d = 96 2) In Triangle ACD 24 + a + b = 180 a + b = 156 3) In Triangle BCD 12 + c + d = 180 c + d = 168 4) at vertex D 132 + b + c = 360 b + c = 228 That's four unknowns and four equations, but the trouble is, those four equations are not independent: we get two different ways to get a + b + c + d = 324 I believe we would need to use trigonometry. We could pick an arbitrary length for AB, and use the Law of Sines to find AC = BC, AD, and BD. From angle CAD, we could use the law of cosines to find length CD, and then use the Law of Sines or Cosines to solve for the angle. That would work, but it's a rather unsatisfying approach, because we would have to use an inverse trig function to give us the angle. There should be a way to do it with pure geometry, without having to use inverse trig functions. From the software I used to create the diagram, I did find that the angle is 78 degrees. Of course,

OpenStudy (anonymous):

what is there a way you can break down into steps?

OpenStudy (bohotness):

Use the law of sines.

OpenStudy (anonymous):

law of what?

OpenStudy (butterflydreamer):

how can angleDAB = 18 and 30?

OpenStudy (anonymous):

I dont even know

OpenStudy (butterflydreamer):

is there a typo? :O

OpenStudy (anonymous):

i wish i knew ima make a educated guess been trying to figure this out forever

OpenStudy (anonymous):

no apparently law of sines makes it possible but i dont know how it works

OpenStudy (perl):

theres another problem with your directions. you can't construct an isosceles triangle with base angle 96 degrees

OpenStudy (perl):

this is an impossible triangle. the angle <ABC must equal to 96 degrees, and 96 + 96 is greater than 180

OpenStudy (anonymous):

law of sines

OpenStudy (anonymous):

but i dont know how to do law of sines

OpenStudy (perl):

|dw:1420882433814:dw|

OpenStudy (perl):

lets start with a diagram

OpenStudy (anonymous):

looks someting like this

OpenStudy (perl):

|dw:1420882597061:dw|

OpenStudy (anonymous):

thanks ill just ask my teacher on monday i know the answer just dont know how to use the law

OpenStudy (anonymous):

hmmm

OpenStudy (anonymous):

ok

OpenStudy (perl):

|dw:1420882787778:dw|

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