Question

Solve The Equations Below, Round to the nearest tenth-thousandth.

Answer 1

\[\log_{10}x=\log_{10}2x ^{2} -2\]

Answer 2

@ganeshie8

Answer 3

@hartnn

Answer 4

Please Show Your Steps.

Answer 5

Because the bases are the same (both are equal to 10), we can just set the insides of the log equal to each other
\[x = 2x^2 -2\]
Solve for x
\[2x^2 -x -2 = 0\]
Now you can factor or use the quadratic equation to solve for x.

Answer 6

(2x-2) (x- 1) ?

Answer 7

Use the quadratic formula:
\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]
From the equation I wrote above
\[2x^2 - x - 2 = 0\]
\[a =2, \ b = -1, \ c = -2\]
So just plug those values into the quadratic equation and solve. Keep in mind the instructions, which ask you to round to the nearest ten thousandth.