Question

A person walks the following route: North 2 meters in 1 second, then turns directly East for 10 meters in 2 seconds, then South for 10 meters in 3 seconds. Draw a position time graph representing this motion. Find the average speeds for each section. What is the final displacement of the person relative to their starting point? (need both magnitude and direction in degrees) Find their average velocity for the whole trip too.

Answer 1

Average speed for each sction would be equal to distance/time taken for each section. calculate it..

Answer 2

okay:)

so like 2/1=2; 10/2=5; 10/3=3.33 ?

Answer 3

yes.

Answer 4

okay! :) so how do i find the final displacement part? with the magnitude and direction in degrees?

Answer 5

Magnitude will be equal to x, can you calculate x? It's equal to the hypotenuse.

Answer 6

ah okie!

so 10^2+8^2=x^2
100+64=x^2
164=x^2
x=12.81 ?

Answer 7

yes. And the direction will be equal to south east direction. Getting it?

Answer 8

yes:) yay!!

okay, so the last part is the average velocity? how can i calculate that? :/

Answer 9

Average velocity = total displacement/total time.

Answer 10

okay! and so total displacement was 12.81 right? :/

Answer 11

yes

Answer 12

okay! :) so total displacement=12.81; time=6 seconds
so 12.81/6=2.135 is the average velocity?

Answer 13

yes

Answer 14

yay!! so we are done with the problem? :O

Answer 15

Yep, don't know the graph thingy :/

Answer 16

ahh okie no worries, i think i can form it with this information!! Thank you for explaining it all!! :D

Answer 17

no problem :-)

Answer 18

:)