Ask your own question, for FREE!
Mathematics 23 Online
OpenStudy (danielbarriosr1):

Please help simplify

OpenStudy (danielbarriosr1):

\[\frac{ \sqrt{10} }{ \sqrt{14} }\]

OpenStudy (misty1212):

HI!

OpenStudy (danielbarriosr1):

Hello

OpenStudy (misty1212):

you can start with \[\frac{\sqrt5}{\sqrt7}\]if you like

OpenStudy (misty1212):

then if you have to rationalize the denominator write \[\frac{\sqrt5\sqrt7}{\sqrt7\sqrt7}=\frac{\sqrt{35}}{7}\]

OpenStudy (danielbarriosr1):

I'm doing carnegie and it is telling me I have to multiply by form of 1

OpenStudy (danielbarriosr1):

what is the form of one @misty1212

OpenStudy (misty1212):

lol "form of 1" i think it means when i multiplied \[\frac{\sqrt5}{\sqrt7}\times \frac{\sqrt7}{\sqrt7}\] the second part is the "form of 1"

OpenStudy (danielbarriosr1):

Oh

OpenStudy (mathmate):

@danielbarriosr1 If you start with the following identities, everything else will follow: \(\sqrt{a} \sqrt{b}=\sqrt{ab}\) \(\dfrac{\sqrt a}{\sqrt b}=\sqrt{\dfrac{a}{b}}\) Example: \(\dfrac{\sqrt{25}}{\sqrt{15}}=\sqrt{\dfrac{25}{15}}=\sqrt{\dfrac{5\times 5}{3\times 5}}=\sqrt{\dfrac{5}{3}}\sqrt{\dfrac{5}{5}}=\sqrt{\dfrac{5}{3}}\)

OpenStudy (danielbarriosr1):

@mathmate so then would it be like @misty1212 said?

OpenStudy (mathmate):

Yes, but in addition to that, I would suggest you to be familiar with the two identities, because they can help you simplify things easier!

OpenStudy (danielbarriosr1):

Oh

OpenStudy (danielbarriosr1):

I got it

OpenStudy (danielbarriosr1):

thanks

OpenStudy (mathmate):

Good! :) You're welcome!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!