Question

question about average velocity

Answer 1

can someone help me, ive been waiting for over an hour @satellite73 @myininaya

Answer 2

@ganeshie8 can you please explain this to me? nobody answered this question since yesterday..

Answer 3

@SolomonZelman can you please help me on this question i posted like 2 days ago? hahah

Answer 4

@freckles would you be able to explain?

Answer 5

step by step please so i could see the broken down version

Answer 6

yes

Answer 7

yeah this question has five parts but i just screenshotted the first one

Answer 8

uhhh would it be 0/8?..

Answer 9

Sorry.
The last sentence would be a help to find the "+C" when you integrate the veloicy function to get the position function.

Answer 10

What is an integral of a velocity function, can you tell me?

Answer 11

(I will remove the mess I made)

Answer 12

You understand why there is a need for integration?

Answer 13

yess

Answer 14

Ok, what is \(\large\color{blue}{\displaystyle\int\limits_{}^{}t^2-9x+18~dt}\) ?

Answer 15

oh I meant to ask, \(\large\color{blue}{\displaystyle\int\limits_{}^{}t^2-9t+18~dt}\)

Answer 16

t^3/3-9t^2/2+18t+C

Answer 17

Yes, that is right.
And this is the position function s(t). (almost the s(t) )

Answer 18

Now, you are given that s(0)=1, what does that tell you about the "C " part ?

Answer 19

im not suree

Answer 20

s(0)=1, simply says that,

(0)^3/3-9(0)^2/2+18(0)+C=1

Answer 21

So the C = ?

Answer 22

1?

Answer 23

yes.

Answer 24

So you have:

\(\large\color{blue}{s(t)=t^3/3-9t^2/2+18t+1}\)

Answer 25

now, you need s(8)

Answer 26

then find the slope for average velocity.

Answer 27

i got a weird numberr...

Answer 28

-57.6

Answer 29

I plugged in 8 for x, using wolfram
http://www.wolframalpha.com/input/?i=s%288%29%3D%288%29%5E3%2F3-9%288%29%5E2%2F2%2B18%288%29%2B1

83/3

Answer 30

So knowing that:
s(0)=1
s(8)=83/3

find the slope (from t=0 to t=8 )

Answer 31

whree do i plug it in?

Answer 32

just use a slope formula

Answer 33

y^2-y^1/x^2-x^1?