Question

@DanJS Derivatives

Answer 1

k

Answer 2

which one looks like one with multiple critical points?

Answer 3

which # you want to do

Answer 4

Try some of the even numbered ones. They're usually (most of the time) harder.

Answer 5

x^2(6-x) will have more than 1

Answer 6

oh no even number ones. im on a time crunch and the hw assignment is on the odd numbers

Answer 7

okay

Answer 8

25) g(x) = x^2 * (6-x)

Answer 9

First, find the 2 derivatives

Answer 10

g'(x) = 12x-2x^2

Answer 11

right?

Answer 12

g ' (x) = 12x - 3x^2

Answer 13

wait are you sure?

Answer 14

I think whenyou multiplied \(x^2 \cdot (-x)\) you mutliplied it as \(x \cdot (-x)\).

Answer 15

\[g(x) = x^2(6-x)\]\[g(x) = 6x^2 -x^3\]\[g'(x) = 12x - 3x^2 \checkmark\]

Answer 16

oh okay

Answer 17

solve g ' (x) = 0, for values of x

Answer 18

x=0 and x= 6

Answer 19

This might help you.

Answer 20

test a number in each of those intervals and see if g '(x) is + or -

Answer 21

one second

Answer 22

wait a second, i just looked back at things

g ' (x) = 12 x - 3x^2

0 = 12x-3x^2 = 3x ( 4 - x)

x = 4 or x= 0

Answer 23

g ' ( -1) = -15 (-) decreasing

g ' ( 1) = (+) increasing

g '( 5) = (-) decreasing