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Mathematics 17 Online
OpenStudy (anonymous):

There is a 20% probability that a person inoculated with a particular vaccine will get the disease anyway. A county health office inoculates 83 people. What is the probability that exactly 10 of them will get the disease at some point in their lives? PLEASE HELP PLEASE

OpenStudy (perl):

this is a binomial problem

OpenStudy (anonymous):

HOW? @perl

OpenStudy (anonymous):

My answer choices are 0.0202 0.0210 0.0412 0.9587

OpenStudy (dan815):

out of 83 people 10 are being infected

OpenStudy (dan815):

there is a 20% prob of failure(infected)

OpenStudy (dan815):

83 choose 10 * 0.2^10*0.8^73

OpenStudy (dan815):

u shud look at small cases to see the pattern

OpenStudy (perl):

There is a 20% probability that a person inoculated with a particular vaccine will get the disease anyway. A county health office inoculates 83 people. What is the probability that exactly 10 of them will get the disease at some point in their lives? Let X = # of people who get disease at some point in their life we want P( X = 10) = (83 choose 10 ) * (.2)^10 * (.8)^73

OpenStudy (dan815):

like say for 5 vaccinated what is the chance that 2 are infected

OpenStudy (perl):

you can also use TI 83 calculator binompdf ( 83, .2, 10)

OpenStudy (anonymous):

im still really confused.. @perl @dan815

OpenStudy (dan815):

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