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Mathematics 18 Online
OpenStudy (anonymous):

Solve. http://static.k12.com/bank_packages/files/media/mathml_f55cd31001ee25e0467b0eb517efa3c1e62c61db_1.gif y =

OpenStudy (anonymous):

@Godlovesme

OpenStudy (anonymous):

@freckles

OpenStudy (freckles):

solve for y

OpenStudy (freckles):

first step: See if you multiply both sides by 3 so we can get rid of that ugly fraction

OpenStudy (freckles):

let me know what you get after performing just this step

OpenStudy (anonymous):

sorry for you wait lag how do i do that sorry to be bother

OpenStudy (freckles):

I want you to try to multiply both sides on 3 and tell me what you think you have as a result of doing that

OpenStudy (anonymous):

so you mean 3x1?

OpenStudy (freckles):

3(y-1)=4y-2

OpenStudy (anonymous):

ok

OpenStudy (freckles):

Second step: use distributive property where possible

OpenStudy (freckles):

that is multiply 3(y-1)

OpenStudy (anonymous):

3y-3=4y-2, right?

OpenStudy (freckles):

great \[y-1=\frac{4y-2}{3} \\ \text{ Multiply both sides by 3 } \\ 3(y-1)=4y-2 \\ \text{ distribute on the left hand side } \\ 3y-3=4y-2\]

OpenStudy (freckles):

so now we want to get our terms with y on one side and the terms without y on the other side

OpenStudy (freckles):

There is a few ways to start out doing this.

OpenStudy (freckles):

Like I might decide to subtract 3y on both sides then add 2 on both sides... You might decide you are going to subtract 4y on both sides then add 3 on both sides. Either way here is fine.

OpenStudy (anonymous):

so 4y+3y?

OpenStudy (freckles):

hmmm... how did you get that?

OpenStudy (freckles):

did you try to subtract 3y on both sides ?

OpenStudy (freckles):

\[-3=4y-3y-2\]

OpenStudy (anonymous):

4y-3y=1y

OpenStudy (freckles):

yes now add 2 on both sides

OpenStudy (freckles):

\[y-1=\frac{4y-2}{3} \\ \text{ Multiply both sides by 3 } \\ 3(y-1)=4y-2 \\ \text{ Distribute on the left hand side } \\ 3y-3=4y-2 \\ \text{ Subtract } 3y \text{ on both sides } \\ -3=4y-3y-2 \\ \text{ add 2 on both sides } \\ -3+2=4y-3y \]

OpenStudy (anonymous):

-3-2=-5

OpenStudy (freckles):

you added 2 on both sides

OpenStudy (anonymous):

oh you said add on give sec

OpenStudy (freckles):

so you should have -3+2

OpenStudy (freckles):

ok

OpenStudy (anonymous):

i got -1

OpenStudy (freckles):

ok sounds great \[ y-1=\frac{4y-2}{3} \\ \text{ Multiply both sides by 3 } \\ 3(y-1)=4y-2 \\ \text{ Distribute on the left hand side } \\ 3y-3=4y-2 \\ \text{ Subtract } 3y \text{ on both sides } \\ -3=4y-3y-2 \\ \text{ add 2 on both sides } \\ -3+2=4y-3y \\ -1=y \]

OpenStudy (anonymous):

so the answer is -1?

OpenStudy (freckles):

yes

OpenStudy (anonymous):

Thanks:)

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