Question

How many moles of carbon dioxide gas can be produced when 5.45 moles of benzene (C6H6) react with excess oxygen? Be sure to show the work that you did to solve this problem.

Unbalanced equation: C6H6 + O2 “yields”/ CO2 + H2O

Answer 1

Balance the thing first

Answer 2

C6H6 + O2 ---> 6 CO2 +3 H2O
2 Oxygen 15 Oxygen to turn 2 into 15, multiply by 15/2


C6H6 + (15/2) O2 ---> 6 CO2 +3 H2O clear fraction, multiply everything by 2


Balanced:
2 C6H6 + 15 O2 ---> 12 CO2 + 6 H2O

Answer 3

Given: 5.45 mol C6H6, infinite O2
Find: ?? mol CO2


[5.45 mol] [?? mol]
2 C6H6 + 15 O2 ---> 12 CO2 + 6 H2O

Answer 4

From the balanced equation the mole ratio is , 2 mol of C6H6 can produce 12 mol CO2

\[\frac{ 12~mol~CO _{2} }{ 2~mol~C _{6}H _{6} }\]

Answer 5

Take the given\[\frac{ 5.45~mol~C6H6 }{ 1 }\]
and multiply it by the mole ratio to convert to moles of Carbon Dioxide produced.